Đáp án:
1, m=188,63g
2, V=4,47l
Giải thích các bước giải:
1,
\(\begin{array}{l}
m = {m_{{N_2}}} + {m_{A{l_2}{{(S{O_4})}_3}}} + {m_{N{H_3}}}\\
\to m = (\dfrac{{11,2}}{{22,4}} \times 28) + (\dfrac{{3 \times {{10}^{23}}}}{{6,022 \times {{10}^{23}}}} \times 342) + (\dfrac{{5,6}}{{22,4}} \times 17) = 188,63g
\end{array}\)
2,
\(\begin{array}{l}
V = {V_{S{O_2}}} + {V_{C{O_2}}} + {V_{{N_2}}}\\
\to V = 22,4 \times (\dfrac{{3,2}}{{64}} + \dfrac{{0,6 \times {{10}^{23}}}}{{6,022 \times {{10}^{23}}}} + \dfrac{{1,4}}{{28}}) = 4,47l
\end{array}\)
