Đáp án:
Giải thích các bước giải:
a) $ \frac{8x - 3}{4} - \frac{3x - 2}{2} = \frac{2x - 1 }{2} + \frac{x + 3}{4} \\\Leftrightarrow 4 (\frac{8x - 3}{4} - \frac{3x - 2}{2} - \frac{2x - 1}{2} + \frac{x + 3}{4} ) = 0 \\\Leftrightarrow 3x = 0 \\\Leftrightarrow x = 0$
b) $ \frac{2 (x + 5) }{3} + \frac{x + 12}{2} - \frac{5 ( x - 2) }{6} = \frac{x}{3} + 11 \\\Leftrightarrow 6 (\frac{2 (x + 5) }{3} + \frac{x + 12}{2} - \frac{5 ( x - 2) }{6} - \frac{x}{3} - 11) = 0 \\\Leftrightarrow 0 = 0 \\\Leftrightarrow x \in R$
