Giải thích các bước giải:
$\text{Bài 4:}$
$a,$ `14/21; 60/72`
$\text{Ta có:}$
`14/21=2/3; 60/72=5/6`
`2/3=12/18; 5/6=15/18`
$\text{Vì}$ `12/18<15/18`
`⇒ 14/21<60/72`
$b,$ `11/54; 22/37`
$\text{Ta có:}$
$\text{Vì}$ `11/54<22/54<22/37`
`⇒ 11/54<22/37`
$c,$ `frac{-2}{15}; frac{-24}{72}`
$\text{Ta có:}$
`frac{-24}{72}=frac{-1}{3}`
`frac{-1}{3}=frac{-5}{15}`, $\text{giữ nguyên}$ `frac{-2}{15}`
$\text{Vì}$ `frac{-2}{15}>frac{-5}{15}`
`⇒frac{-2}{15}>frac{-24}{72}`
$d,$ `24/49; 23/45`
$\text{Ta có:}$
`24/49=1080/2205; 23/45=1127/2205`
$\text{Vì}$ `1080/2205<1127/2205`
`⇒ 24/49<23/45`
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