Hình chóp S.ABC có SA = a , SB = b , SC = c , đôi 1 vuông góc với nhau , tính thể tích khối chóp? Em có thắc mắc là công thức khối chóp là V = 1/3 * S.đáy * Cao Theo đề bài thì đáy là ABC , nhưng trong lời giải thì -sau khi chứng minh SA vuông góc với (SBC) thì lại dùng (SBC) thay vì (ABC) ạ ?

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