`n_(Mg)=(1,2)/24=0,05(mol)`
Phương trình hóa học:
`Mg+2HCl->MgCl_2+H_2↑`
Theo PTHH: `n_(HCl)=2n_(Mg)=2.0,05=0,1(mol)`
`m_(HCl)=0,1.36,5=3,65(g)`
Theo PTHH: `n_(MgCl_2)=n_(H_2)=n_(Mg)=0,05(mol)`
`m_(MgCl_2)=0,05.95=4,75(mol)`
`V_(H_2)=0,05.22,4=1,12(l)`