Mg + 2HCl → MgCl2 + H2↑
a) nMg = 14/24 = 0,58(mol)
nHCl = 2 (mol)
nMg/1 < nHCl/2 → HCl dư.
=> nMgCl2 = nH2 = 0,58 (mol)
mMgCl2 = 0,58.95 = 55,1 (g)
VH2 = 0,58.22,4 = 12,992 (lit)
b) Vdd = VMg + VHCl = 0,58.22,4 + 1
= 13,992 (lít)
CM(MgCl2) = 0,58/13,992 = 0,04 ( M )
CM(H2O) = 0,04 (M)