Giải thích các bước giải:
Phản ứng xảy ra:
`Zn+2HCl->ZnCl_2+H_2(1)`
`ZnO+2HCl->ZnCl_2+H_2O(2)`
`n_{H_2}=(4,48)/(22,4)=0,2(mol)`
`m_{Zn}=0,2.65=13(gam)`
`mct_{HCl}=(120.18,25)/(100)=21,9(gam)`
`->n_{HCl}=(21,9)/(36,5)=0,6(mol)`
`->n_{HClpu(1)}=0,2.2=0,4(mol)`
`->n_{HClpu(2)}=0,6-0,4=0,2(mol)`
`->m_{ZnO}=1/2 .0,2.(65+16)=8,1(gam)`
`m_{hh}=m_{Zn}+m_{ZnO}=8,1+13=21,1(gam)`
`%m_{Zn}=13/(21,1).100=61,61%`
`%m_{ZnO}=100%-61,61%=38,39%`
`m_{ZnCl_2pu(1)(2)}=(0,2+1/2 .0,2).136=40,8(gam)`
`m_{dd(spu)}=21,1+120-0,2.2=140,7(gam)`
`%m_{muoi(spu)}=(40,8)/(140,7).100≈29%`