Đáp án đúng: D
8,96 (l).
$\begin{array}{l}\text{Ba}\,\text{+}\,\text{2}{{\text{H}}_{\text{2}}}\text{O}\,\xrightarrow{{}}\,\text{Ba(OH}{{\text{)}}_{\text{2}\,}}\,\text{+}\,\,{{\text{H}}_{\text{2}}}\\\text{0,1}\,\,\,\,\,\,\,\,\,\xrightarrow{{}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{0,1}\,\xrightarrow{{}}\,\,\text{0,1}\\\text{Al}\,\,\,\text{+}\,\,\text{O}{{\text{H}}^{\text{-}}}\,\text{+3}{{\text{H}}_{\text{2}}}\text{O}\,\xrightarrow{{}}\,\text{Al(OH)}_{\text{4}}^{\text{-}}\,\text{+}\,\frac{\text{3}}{\text{2}}{{\text{H}}_{\text{2}}}\\\text{0,2}\,\leftarrow \,\text{0,2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\xrightarrow{{}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{0,3}\\\Rightarrow \,{{\text{V}}_{{{\text{H}}_{\text{2}}}}}\,\text{=}\,\text{8,96}\,\,\text{lit}\end{array}$