Em tham khảo nha:
\(\begin{array}{l}
(1)\,2{H_2}S + S{O_2} \to 3S + 2{H_2}O\\
(2)3S + 6NaOH \to N{a_2}S{O_3} + 2N{a_2}S + 3{H_2}O\\
A:N{a_2}S{O_3}\\
F:N{a_2}S\\
(3)N{a_2}S{O_3} + 2HCl \to 2NaCl + S{O_2} + {H_2}O\\
B:S{O_2}\\
(4)S{O_2} + NaOH \to NaHS{O_3}\\
C:NaHS{O_3}\\
(5)\,NaHS{O_3} + NaOH \to N{a_2}S{O_3} + {H_2}O\\
(6)\,N{a_2}S{O_3} + Ba{(OH)_2} \to 2NaOH + BaS{O_3}\\
(7)\,N{a_2}S + 2HCl \to 2NaCl + {H_2}S\\
(8)\,{H_2}S + NaOH \to NaHS + {H_2}O\\
H:NaHS\\
(9)\,NaHS + NaOH \to N{a_2}S + {H_2}O\\
(10)N{a_2}S + 2AgN{O_3} \to A{g_2}S + 2NaN{O_3}
\end{array}\)