Đáp án:
$a/$
$2KMnO4 + 16HClđ -to-> 2KCl + 2MnO2 + 5Cl2 + 8H2O$
$2Fe + 3Cl2 -to-> 2FeCl3$
$FeCl3 + 3NaOH --> Fe(OH)3 + 3NaCl$
$Fe(OH)3 + 3HCl --> FeCl3 + 3H2O$
$Fe + 2FeCl3 --> 3FeCl2$
$FeCl2 + 2AgNO3 --> Fe(NO3)2 + 2AgCl$
$b/$
$2NaCl + 2H2O -$$đpdd có màn ngăn$$-> 2NaOH + H2 + Cl2$
$2Na + Cl2 -to-> 2NaCl$
$2NaCl + H2SO4đ -to-> Na2SO4 + 2HCl$
$HCl + AgNO3 --> AgCl + HNO3$
$c/$
$MnO2 + 4HCl -to-> MnCl2 + Cl2 + 2H2O$
$2Al + 3Cl2 -to-> 2AlCl3$
$AlCl3 + 3NaOH --> Al(OH)3 + 3NaCl$
$2Al(OH)3 -to-> Al2O3 + 3H2O$
$d/$
$14HClđ + K2Cr2O7 -to-> 2KCl + 2CrCl3 + 3Cl2 + 7H2O$
$3Cl2 + 6KOH -to-> KClO3 + 5KCl + 3H2O$
$2KClO3 -to-> 2KCl + 3O2$
$2KCl + 2H2O -$$đpdd có màn ngăn$$-> 2KOH + H2 + Cl2$
$Cl2 + H2 - as -> 2HCl$
$2HCl + Na -> 2NaCl + H2$
$2NaCl + 2H2O -$$đpdd có màn ngăn$$-> 2NaOH + H2 + Cl2$
$NaOH + HCl -> NaCl + H2O$
$e/$
$Fe + 2HCl --> FeCl2 + H2$
$FeCl2 + 2NaOH --> Fe(OH)2 + 2NaCl$
$4Fe(OH)2 + O2 -to-> 2Fe2O3 + 4H2O$
$Fe2O3 + 6HCl --> 2FeCl3 + 3H2O$
$FeCl3 + 3AgNO3 --> Fe(NO3)3 + 3AgCl$
