Đáp án:
Giải thích các bước giải:
\(\left\{ \begin{gathered}C{H_3}COOH:a(mol) \hfill \\{C_2}{H_5}OH:b(mol) \hfill \\ \end{gathered} \right.\left. {\left| \begin{gathered}\xrightarrow{K}{H_2}:0,15mol \hfill \\\xrightarrow{{N{a_2}C{O_3}}}C{O_2}:0,05mol \hfill \\ \end{gathered} \right.} \right\} \Rightarrow \left\{ \begin{gathered}{\text{a + b = 0,15}}{\text{.2}} \hfill \\a = 2.0,05 \hfill \\ \end{gathered} \right. \Rightarrow \left\{ \begin{gathered}a = 0,1 \hfill \\b = 0,2 \hfill \\ \end{gathered} \right.\)
\({\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} C{H_3}COOH + {C_2}{H_5}OH\mathop \leftrightarrows \limits^{{H_2}S{O_4}} C{H_3}COO{C_2}{H_5} + {H_2}O\)
\(\begin{align}& bd(mol)\,\,\,0,1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,2 \\ & pu(mol)\,\,\,0,1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\to 0,1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\to 0,1 \\ & cb(mol)\,\,\,\,0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,1 \\ & m{{\,}_{ly\,thuyet}}=0,1.88=8,8gam \\ & m\,{{\,}_{thuc.te}}=m\,{{\,}_{ly\,thuyet}}.\dfrac{H%}{100}=8,8.\dfrac{60}{100}=5,28gam \\ \end{align}\)
