Đáp án:
\(\begin{array}{l}
a.R = 12,5\Omega \\
b.I = 2,4A\\
c.{U_1} = 24V\\
d.{I_2} = 1,2A\\
e.Q = 2160J
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a.\\
{R_{23}} = \dfrac{{{R_2}{R_3}}}{{{R_2} + {R_3}}} = \dfrac{{5.5}}{{5 + 5}} = 2,5\Omega \\
R = {R_1} + {R_{23}} = 10 + 2,5 = 12,5\Omega \\
b.\\
I = \dfrac{U}{R} = \dfrac{{30}}{{12,5}} = 2,4A\\
c.\\
I = {I_1} = 2,4A\\
{U_1} = {I_1}{R_1} = 2,4.10 = 24V\\
d.\\
{U_2} = {U_3} = {U_{23}} = U - {U_1} = 30 - 24 = 6V\\
{I_2} = \dfrac{{{U_2}}}{{{R_2}}} = \dfrac{6}{5} = 1,2A\\
e.\\
Q = \dfrac{{U_3^2}}{{{R_3}}}t = \dfrac{{{6^2}}}{5}.300 = 2160J
\end{array}\)
