$1)$ĐKXĐ: $x\leq4$
$2\sqrt{2}-\sqrt{4-x}=0$
`<=>`$\sqrt{4-x}=2\sqrt{2}$
`<=>`$4-x=8$
`<=>`$x=-4 (t/m)$
Vậy $x=-4$
$2)$ĐKXĐ: $x\geq0$
$\frac{5}{3}\sqrt{6x}+\frac{1}{3}\sqrt{6x}+\sqrt{24x}=2$
`<=>`$\frac{5}{3}\sqrt{6x}+\frac{1}{3}\sqrt{6x}+2\sqrt{6x}=3$
`<=>`$4\sqrt{6x}=2$
`<=>`$\sqrt{6x}=\frac{1}{2}$
`<=>`$6x=\frac{1}{4}$
`<=>`$x=\frac{1}{24} (t/m)$
Vậy $x=\frac{1}{24}$
