$#Dứa$
a, (2x - 3)² = (2x)² - 2.2x.3 + 3² = 4x² - 12x + 9
b, ($\frac{3}{2}$-x)² = ($\frac{3}{2}$)² - 2.$\frac{3}{2}$.x + x² = $\frac{9}{4}$ - 3x + x²
c, (2x + 3y)² = (2x)² - 2.2x.3y + 3y² = 4x² - 12xy + 9y²
d, (a² - 2)² = (a²)² - 2.a².a + 2² = $a^{4}$ - 4a² + 4
e, (2x - y + z)² = [(2x - y) + z]² = (2x - y)² + 2(2x - y) . z + z² = 4x² - 4xy + y² + 4xz - 2xz + z²
* Sorry mải buôn quá nên quên khum lm bài =v=