Khẳng định nào sau đây là đúng ?
A.\({\log _2}\left( {\dfrac{x}{y}} \right) = {\log _2}x - {\log _2}y\,\,\forall \,x,y > 0.\)
B.\({\log _2}\left( {\dfrac{x}{y}} \right) = {\log _2}x + {\log _2}y\,\,\forall \,x,y > 0.\)
C.\({\log _2}\left( {\dfrac{x}{y}} \right) = \dfrac{x}{{{{\log }_2}y}}\,\,\forall \,x,y > 0,\,y
e 1.\)
D.\({\log _2}\left( {\dfrac{x}{y}} \right) = \dfrac{{{{\log }_2}x}}{{{{\log }_2}y}}\,\,\forall \,x,y > 0,\,y
e 1.\)
A.\({\log _2}\left( {\dfrac{x}{y}} \right) = {\log _2}x - {\log _2}y\,\,\forall \,x,y > 0.\)
B.\({\log _2}\left( {\dfrac{x}{y}} \right) = {\log _2}x + {\log _2}y\,\,\forall \,x,y > 0.\)
C.\({\log _2}\left( {\dfrac{x}{y}} \right) = \dfrac{x}{{{{\log }_2}y}}\,\,\forall \,x,y > 0,\,y
e 1.\)
D.\({\log _2}\left( {\dfrac{x}{y}} \right) = \dfrac{{{{\log }_2}x}}{{{{\log }_2}y}}\,\,\forall \,x,y > 0,\,y
e 1.\)
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