`n_{MnO_2}={87}/{87}=1(mol)`
`MnO_2+4HCl->MnCl_2+Cl_2+2H_2O`
`n_{Cl_2}=n_{MnO_2}=1(mol)`
`n_{NaOH}=0,5.5=2,5(mol)`
`Cl_2+2NaOH->NaCl+NaClO+H_2O`
Do `2.1<2,5->NaOH` dư
`n_{NaCl}=n_{NaClO}=1(mol)`
`n_{NaOH(du)}=2,5-1.2=0,5(mol)`
`m_{dd\ spu}=500.1,25+1.71=696(g)`
`C_{M\ NaCl}=C_{M\ NaClO}={1}/{0,5}=2M`
`C_{M\ NaOH(du)}={0,5}/{0,5}=1M`
`C\%_{NaCl}={1.58,5}/{696}.100≈8,41\%`
`C\%_{NaClO}={1.74,5}/{696}.100≈10,7\%`
`C\%_{NaOH(du)}={0,5.40}/{696}.100≈2,87\%`