Đáp án đúng: D
8,74 gam và 0,1875 mol
$\left\{ \begin{array}{l}24{{n}_{Mg}}\,+\,56{{n}_{Fe}}\,=\,1,92\,gam\\\frac{{{n}_{Mg}}}{{{n}_{Fe}}}\,=\,\frac{1}{3}\end{array} \right.\,\Rightarrow \,\left\{ \begin{array}{l}{{n}_{Mg}}\,=\,0,01\\{{n}_{Fe}}\,=\,0,03\end{array} \right.$
$\left\{ \begin{array}{l}{{n}_{NO}}\,+\,{{n}_{N{{O}_{2}}}}\,=\,0,0775\,mol\\3{{n}_{NO}}\,+\,{{n}_{N{{O}_{2}}}}\,=\,2{{n}_{Mg}}\,+\,3{{n}_{Fe}}\,=\,0,11\,mol\end{array} \right.\,\Rightarrow \,\left\{ \begin{array}{l}{{n}_{NO}}\,=\,0,01625\,mol\\{{n}_{N{{O}_{2}}}}\,=\,0,06125\,mol\end{array} \right.$
mmuối =${{m}_{KL}}\,+\,62{{n}_{e}}\,=\,1,92\,+\,62.0,11\,=\,8,74\,gam$
${{n}_{HN{{O}_{3}}}}\,=\,{{n}_{NO}}\,+\,{{n}_{N{{O}_{2}}}}\,+\,{{n}_{e}}\,=\,0,1875\,mol$