Khi khai triển $\displaystyle P\left( x \right)={{\left( x+y \right)}^{6}}$ thành đa thức thì:
A. $\displaystyle P\left( x \right)={{x}^{6}}-6{{x}^{5}}y+15{{x}^{4}}{{y}^{2}}-20{{x}^{3}}{{y}^{3}}+15{{x}^{2}}{{y}^{4}}-6x{{y}^{5}}+{{y}^{6}}$
B. $\displaystyle P\left( x \right)={{x}^{6}}+6{{x}^{5}}y+15{{x}^{4}}{{y}^{2}}+20{{x}^{3}}{{y}^{3}}+15{{x}^{2}}{{y}^{4}}+6x{{y}^{5}}+{{y}^{6}}$
C. $\displaystyle P\left( x \right)={{x}^{6}}+6{{x}^{5}}y-15{{x}^{4}}{{y}^{2}}-20{{x}^{3}}{{y}^{3}}-15{{x}^{2}}{{y}^{4}}-6x{{y}^{5}}+{{y}^{6}}$
D. $\displaystyle P\left( x \right)={{x}^{6}}+6{{x}^{5}}y+15{{x}^{4}}{{y}^{2}}+20{{x}^{3}}{{y}^{3}}-15{{x}^{2}}{{y}^{4}}-6x{{y}^{5}}-{{y}^{6}}$
A. $\displaystyle P\left( x \right)={{x}^{6}}-6{{x}^{5}}y+15{{x}^{4}}{{y}^{2}}-20{{x}^{3}}{{y}^{3}}+15{{x}^{2}}{{y}^{4}}-6x{{y}^{5}}+{{y}^{6}}$
B. $\displaystyle P\left( x \right)={{x}^{6}}+6{{x}^{5}}y+15{{x}^{4}}{{y}^{2}}+20{{x}^{3}}{{y}^{3}}+15{{x}^{2}}{{y}^{4}}+6x{{y}^{5}}+{{y}^{6}}$
C. $\displaystyle P\left( x \right)={{x}^{6}}+6{{x}^{5}}y-15{{x}^{4}}{{y}^{2}}-20{{x}^{3}}{{y}^{3}}-15{{x}^{2}}{{y}^{4}}-6x{{y}^{5}}+{{y}^{6}}$
D. $\displaystyle P\left( x \right)={{x}^{6}}+6{{x}^{5}}y+15{{x}^{4}}{{y}^{2}}+20{{x}^{3}}{{y}^{3}}-15{{x}^{2}}{{y}^{4}}-6x{{y}^{5}}-{{y}^{6}}$
Loga
Hóa Học lớp 12
