` 4P + 5O_2 \overset{t^0\ }{\to} 2P_2O_5`
` n_(P) = (62)/31 =2\ mol`
Theo PT ta có ` n_(P_2O_5) = 1/2 . n_(P) = 1/2 . 2 = 1\ mol`
`\to m_(P_2O_5) = 1 . ( 31*2 + 16*5 ) = 142`
Chọn `A`
$ n_{P} = \dfrac{m}{M} = \dfrac{ 62 }{ 31 } = 2 (mol) $
$ 4P + 5O_2 \xrightarrow{t^o} 2P_2O_5 $
Theo phương trình :
$ n_{P_2O_5} = \dfrac{2}{4} × n_{P} = \dfrac{2}{4} × 2 = 1 (mol) $
$ \to m_{P_2O_5} = n × M = 1 × 142 = 142 (g) $
$ \to A $
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Ê lò re endhhdhdhdhdhdhdhdhdhdhd
tìm n để 3n-1/3n-4 có giá trị nguyên
Trong công thức SO3, lưu huỳnh có hóa trị là *
so sánh 10^2020+1/10^2021+1 và 10^2020-11/10^2021-10
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p=(căn x -4 phần căn x (căn x -2) +3 phần căn x-2 ) chia căn x phần căn x -2)
Các bạn làm hộ mình nhé!Mình đang cần gấp
làm hộ mik nha love you chu cà mo
1,Bây giờ là 4 giờ. Sau ít nhất ? phút thì kim giờ và kim phút chập nhau. 2,1 người đi bộ 15 phút rồi đi xe máy trong 7 phút thì đến chợ. Tính qđ người đó đi bộ biết qđ từ nhà đến chợ là 6km và v xe máy gấp 5 lần v đi bộ.
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