Đáp án:
\(C{\% _{CuS{O_4}}} = 18\% ;{C_{M{\text{ CuS}}{{\text{O}}_4}}} = 1,8M\)
Giải thích các bước giải:
Ta có:
\({m_{dd{\text{Cu S}}{{\text{O}}_4}}} = 321,5.1,6 = 500{\text{ gam;}}{{\text{V}}_{dd}} = 0,3125{\text{ lít}}\)
\({n_{CuS{O_4}.5{H_2}O}} = {n_{CuS{O_4}{\text{ trong dd }}}} = \frac{{140,625}}{{64 + 96 + 18.5}} = 0,5625{\text{ mol}} \to {{\text{m}}_{CuS{o_4}}} = 0,5625.160 = 90{\text{ gam}}\)
\( \to C{\% _{CuS{O_4}}} = \frac{{90}}{{500}}.100\% = 18\% ;{C_{M{\text{ CuS}}{{\text{O}}_4}}} = \frac{{0,5625}}{{0,3125}} = 1,8M\)