a) 4x-10=14
⇔ 4x=14+10
⇔ 4x=24
⇔ x = 6
b) 2(x-3)+4(x+4)=58
⇔ 2x -6 +4x+16=58
⇔ 2x+4x = 58-16+6
⇔ 6x = 48
⇔ x = 8
c) 5 ( x+2 ) +4(-x+2)=10
⇔ 5x+10-4x+8 =10
⇔ x = 10-10-8
⇔ x =-8
d) 4(x+7)=3(x-2)
⇔ 4x +28 = 3x-6
⇔ x = -6-28
⇔ x =-34
e) 5(x-10)+12=4(x+12)-10
⇔ 5x -50 +12 = 4x +48 -10
⇔ x = 48-10+50-12
⇔ x =76
f) |x-3| =10
⇔ \(\left[ \begin{array}{l}x-3=10\\x-3=-10\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=13\\x=-7\end{array} \right.\)
g) |2x-70| = 18
⇔\(\left[ \begin{array}{l}2x-70=18\\2x-70=-18\end{array} \right.\)
⇔\(\left[ \begin{array}{l}2x = 88\\2x=52\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=44\\x=26\end{array} \right.\)
h) 5-|10-x|=4
⇔ |10-x| =-1
⇔ \(\left[ \begin{array}{l}10-x=-1\\10-x=9\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x = 11\\x=9\end{array} \right.\)
i ) 25-3|x-2|=1
⇔ -3|x-2| = 24
⇔ | x-2 | = -8
⇔ \(\left[ \begin{array}{l}x-2=-8\\x-2=8\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x=-6\\x=10\end{array} \right.\)
j ) (5x-10)(x-2)=0
⇔ \(\left[ \begin{array}{l}5x-10=0\\x-2=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}5x=10\\x=2\end{array} \right.\)
⇔ x = 2
k ) 7x+14.(130-36x)=0
⇔ 7x +1820 -504x =0
⇔ -497x = -1820
⇔ x = $\frac{260}{71}$
