`1) 4x(x-5) - (x-1)(4x-3) = 5`
`=>( 4x^2 -20x) - (4x^2 - 3x - 4x + 3) = 5`
`=> 4x^2 - 20x - 4x^2 + 3x + 4x - 3 = 5`
`=> -13x - 3 = 5`
`=> -13x = 8`
`=> x = -8/13`
Vậy `x=-8/13`
`2) (3x-4)(x-2) = 3x(x-9) -3`
`=> 3x^2 - 6x - 4x + 8 = 3x^2 - 27x - 3`
`=> 3x^2 - 6x - 4x - 3x^2 + 27x = -3 - 8`
`=> 17x = -11`
`=> x = -11/17`
Vậy `x=-11/17`
`3) (x-5)(x-4) - (x+1)(x-2) = 7`
`=> (x^2 - 4x - 5x + 20) - (x^2 - 2x + x - 2) =7`
`=> x^2 - 4x - 5x + 20 - x^2 + 2x - x + 2 =7`
`=> -8x + 22 = 7`
`=> -8x = -15`
`=> x = 15/8`
Vậy `x = 15/8`
`4) 5x(x-3) = (x-2)(5x-1) -5`
`=> 5x^2 - 15x = 5x^2 - x - 10x + 2 - 5`
`=> 5x^2 - 15x - 5x^2 + x + 10x = 2 -5`
`=> -4x = -3`
`=> x = 3/4`
Vậy `x=3/4`
`5) (x-5)(x-1) = (x-1)(x-2) `
`=> x^2 - x - 5x + 5 = x^2 - 2x - x + 2`
`=> x^2 - x - 5x - x^2 + 2x + x = 2-5`
`=> -3x =-3`
`=> x = 1`
Vậy `x=1`