a. 1$\frac{4}{13}$ + $\frac{15}{22}$ + $\frac{9}{13}$ + $\frac{7}{22}$ - 2
=$\frac{17}{13}$ + $\frac{15}{22}$ + $\frac{9}{13}$ + $\frac{7}{22}$ - 2
= ( $\frac{17}{13}$ + $\frac{9}{13}$ ) + ( $\frac{15}{22}$ + $\frac{7}{22}$) - 2
= $\frac{26}{13}$ + $\frac{22}{22}$ - 2
= 2 + 1 -2
= 1
d. $\frac{12}{15}$ - /$\frac{-4}{24}$ / + $\frac{8}{60}$ - ($\frac{-2020}{2019}$ )
= $\frac{12}{15}$ - $\frac{4}{24}$ + $\frac{8}{60}$ + $\frac{2020}{2019}$
= $\frac{4}{5}$ - $\frac{1}{6}$ + $\frac{2}{15}$ + $\frac{2020}{2019}$
=( $\frac{4}{5}$ - $\frac{1}{6}$ + $\frac{2}{15}$ ) + $\frac{2020}{2019}$
= ( $\frac{24}{30}$ - $\frac{5}{30}$ + $\frac{4}{30}$ ) + $\frac{2020}{2019}$
= $\frac{23}{30}$ + $\frac{2020}{2019}$
= $\frac{107037}{60570}$