`(80)/(x)=1+(1)/(3)+(80-x)/(x+20)`
`<=>(80)/(x)-(80-x)/(x+20)=(4)/(3)`
`<=>(80x+1600-80x+x^2)/(x.(x+20))=4/3`
`<=>(x^2+1600).3=4.x.(x+20)`
`<=>3x^2+4800=4x^2+80x`
`<=>x^2+80x-4800=0`
`<=>(x-40).(x+120)=0`
`<=>`\(\left[ \begin{array}{l}x=40\\x=-120\end{array} \right.\)