Đáp án:
a)$\frac{1}{x}$ .$\frac{6x}{y}$
=$\frac{6}{y}$
b)$\frac{2x²}{y}$ .$\frac{3xy²}{1}$
=6x³y
c)$\frac{15x}{7y³}$ .$\frac{2y²}{x²}$
=$\frac{30}{7xy}$
d)$\frac{2x²}{x-y}$. $\frac{y}{5x³}$
=$\frac{2x}{(X-y)5X}$
=$\frac{2Y}{5x²-5xy}$
=$\frac{2}{5x²-5xy}$
e)$\frac{5x+10}{4x-8}$ .$\frac{4-2x}{x+2}$
=$\frac{5(x+2)(-2(x-2))}{4(x-2)(x+2)}$
=$\frac{-5}{2}$
f)$\frac{x²-36}{2x+10}$ .$\frac{3}{6-x}$
=$\frac{(x-6)(x+6)}{2x+10}$ .$\frac{3}{-(x-6)}$
=-$\frac{3(x+6)}{2(x+5)}$
g)$\frac{x²-9y²}{x²y²}$ .$\frac{3xy}{2x-6y}$
=$\frac{(x-3y)(x+3y).3xy}{x²y².2(x-3y)}$
=$\frac{3(x+3y)}{2xy}$
Giải thích các bước giải:
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