\(\left|3x-5\right|=4\)
th1: \(3x-5\ge0\Leftrightarrow3x\ge5\Leftrightarrow x\ge\dfrac{5}{3}\)
\(\Rightarrow\left|3x-5\right|=4\Leftrightarrow3x-5=4\Leftrightarrow3x=4+5=9\Leftrightarrow x=\dfrac{9}{3}=3\left(tmđk\right)\)
th2: \(3x-5< 0\Leftrightarrow3x< 5\Leftrightarrow x< \dfrac{5}{3}\)
\(\Rightarrow\left|3x-5\right|=4\Leftrightarrow5-3x=4\Leftrightarrow3x=5-4=1\Leftrightarrow x=\dfrac{1}{3}\left(tmđk\right)\)
vậy \(x=3;x=\dfrac{1}{3}\)