Đáp án:
\( V = 937,5{\text{ ml}}\)
Giải thích các bước giải:
Phản ứng xảy ra:
\({C_6}{H_{12}}{O_6}\xrightarrow{{men}}2{C_2}{H_5}OH + 2C{O_2}\)
Ta có:
\({n_{{C_6}{H_{12}}{O_6}}} = \frac{{1800}}{{180}} = 10{\text{ mol}}\)
\( \to {n_{{C_2}{H_5}OH{\text{ lt}}}} = 2{n_{{C_6}{H_{12}}{O_6}}} = 10.2 = 20{\text{ mol}}\)
\( \to {n_{{C_2}{H_5}OH}} = 20.75\% = 15{\text{ mol}}\)
\( \to {m_{{C_2}{H_5}OH}} = 15.46 = 690{\text{ gam}}\)
\( \to {V_{{C_2}{H_5}OH}} = \frac{{690}}{{0,8}} = 862,5{\text{ ml}}\)
\( \to V = \frac{{862,5}}{{92\% }} = 937,5{\text{ ml}}\)
