Em tham khảo nha :
\(\begin{array}{l}
1)\\
a)\\
2Al + 6HCl \to 2AlC{l_3} + 3{H_2}\\
{n_{HCl}} = 0,3 \times 1 = 0,3mol\\
{n_{Al}} = \dfrac{{{n_{HCl}}}}{3} = 0,1mol\\
{m_{Al}} = 0,1 \times 27 = 2,7g\\
b)\\
{n_{AlC{l_3}}} = {n_{Al}} = 0,1mol\\
{m_{AlC{l_3}}} = 0,1 \times 133,5 = 13,35g\\
AlC{l_3}:\text{Nhôm clorua}\\
c)\\
{n_{{H_2}}} = \dfrac{{{n_{HCl}}}}{2} = 0,15mol\\
{V_{{H_2}}} = 0,15 \times 22,4 = 3,36l\\
2)\\
a)\\
4P + 5{O_2} \xrightarrow{t^0} {P_2}{O_5}\\
{n_P} = \dfrac{{12,4}}{{31}} = 0,4mol\\
{P_2}{O_5}:\text{DiPhotphoPentanOxit}\\
{n_{{P_2}{O_5}}} = \dfrac{{{n_P}}}{2} = 0,2mol\\
{m_{{P_2}{O_5}}} = 0,2 \times 142 = 28,4g\\
b)\\
{n_{{O_2}}} = \dfrac{5}{4}{n_P} = 0,5mol\\
{V_{{O_2}}} = 0,5 \times 22,4 = 11,2l\\
{V_{kk}} = 5{V_{{O_2}}} = 5 \times 11,2 = 56l
\end{array}\)
