Đáp án:
Giải thích các bước giải:
\(\begin{array}{l}
1.\left( {x + 3} \right) \in U\left( 6 \right)\\
\to \left[ \begin{array}{l}
x + 3 = 6\\
x + 3 = - 6\\
x + 3 = 3\\
x + 3 = - 3\\
x + 3 = 2\\
x + 3 = - 2\\
x + 3 = 1\\
x + 3 = - 1
\end{array} \right. \to \left[ \begin{array}{l}
x = 3\\
x = - 9\\
x = - 1\\
x = - 5\\
x = - 2\\
x = - 4
\end{array} \right.\\
2.\left( {x - 1} \right) \in U\left( {14} \right)\\
\to \left[ \begin{array}{l}
x - 1 = 14\\
x - 1 = - 14\\
x - 1 = 7\\
x - 1 = - 7\\
x - 1 = 2\\
x - 1 = - 2\\
x - 1 = 1\\
x - 1 = - 1
\end{array} \right. \to \left[ \begin{array}{l}
x = 15\\
x = - 13\\
x = 8\\
x = - 6\\
x = 3\\
x = - 1\\
x = 2\\
x = 0
\end{array} \right.\\
3.\left( {x - 4} \right) \in U\left( {27} \right)\\
\to \left[ \begin{array}{l}
x - 4 = 27\\
x - 4 = - 27\\
x - 4 = 9\\
x - 4 = - 9\\
x - 4 = 3\\
x - 4 = - 3\\
x - 4 = 1\\
x - 4 = - 1
\end{array} \right. \to \left[ \begin{array}{l}
x = 31\\
x = - 23\\
x = 13\\
x = - 5\\
x = 7\\
x = 1\\
x = 5\\
x = 3
\end{array} \right.\\
4.\left( {x + 3} \right) \in U\left( {12} \right)\\
\to \left[ \begin{array}{l}
x + 3 = 12\\
x + 3 = - 12\\
x + 3 = 6\\
x + 3 = - 6\\
x + 3 = 2\\
x + 3 = - 2\\
x + 3 = 1\\
x + 3 = - 1
\end{array} \right. \to \left[ \begin{array}{l}
x = 9\\
x = - 15\\
x = 3\\
x = - 9\\
x = - 1\\
x = - 5\\
x = - 2\\
x = - 4
\end{array} \right.
\end{array}\)
