Đáp án:
e)x+$\frac{5}{8}$x-$\frac{12}{16}$x=1
<=>x(1+$\frac{5}{8}$-$\frac{12}{16}$)=1
<=>x(1+$\frac{5}{8}$-$\frac{3}{4}$)=1
<=>x($\frac{8}{8}$+$\frac{5}{8}$-$\frac{6}{8}$)=1
<=>x$\frac{7}{8}$=1 <=>x=1:$\frac{7}{8}$
<=>x=1.$\frac{8}{7}$ <=>x=$\frac{8}{7}$
Vậy x=$\frac{8}{7}$
f)(x+$\frac{1}{2}$)*2-$\frac{1}{3}$= $\frac{6}{9}$
<=>(x+$\frac{1}{2}$)*2-$\frac{1}{3}$=$\frac{2}{3}$
<=>(x+$\frac{1}{2}$)*2=$\frac{2}{3}$+$\frac{1}{3}$
<=>(x+$\frac{1}{2}$)*2=1 <=>\(\left[ \begin{array}{l}x+\frac{1}{2}=1\\x+\frac{1}{2}=-1\end{array} \right.\)
<=>\(\left[ \begin{array}{l}x=1-\frac{1}{2}\\x=-1-\frac{1}{2}\end{array} \right.\)
<=>\(\left[ \begin{array}{l}x=\frac{1}{2}\\x=-\frac{3}{2}\end{array} \right.\)
Vậy...
Cho mih xin ctlhn nha
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