Đáp án:
$\begin{array}{l}
\dfrac{9}{5}{x^2} + \dfrac{9}{5}x = - x + \dfrac{2}{5}\\
\Rightarrow \dfrac{9}{5}{x^2} + \dfrac{{14}}{5}x - \dfrac{2}{5} = 0\\
\Rightarrow 9{x^2} + 14x - 2 = 0\\
\Rightarrow \left\{ \begin{array}{l}
a = 9\\
b = 14\\
c = - 2
\end{array} \right.
\end{array}$
