`Zn+2HCl->ZnCl_2+H_2`
`CuO+H_2->Cu+H_2O`
`n_{Zn}=(3,25)/(65)=0,05mol`
`n_{HCl}=2.0,05=0,1mol`
`mdd_{HCl}=(0,1.36,5)/(7,3%)=50g`
`n_{H_2}=n_{Zn}`
`n_{CuO}=6/(64+16)=0,075mol`
`n_{H_2}<n_{CuO}`
`n_{CuO(du)}=0,075-0,05=0,025mol`
`m_{CuO(du)}=0,025.(64+16)=2g`
`n_{Cu}=n_{H_2}`
`m_{Cu}=0,05.64=3,2g`