Em tham khảo nha :
\(\begin{array}{l}
F{e_x}{O_y} + 2yHCl \to xFeC{l_{\frac{{2y}}{x}}} + y{H_2}O\\
{n_{HCl}} = 0,03 \times 2 = 0,06mol\\
{n_{F{e_x}{O_y}}} = \dfrac{{{n_{HCl}}}}{{2y}} = \dfrac{{0,03}}{y}\\
{M_{F{e_x}{O_y}}} = 1,6:\dfrac{{0,03}}{y} = \dfrac{{160}}{3}y\\
\Rightarrow 56x + 16y = \dfrac{{160}}{3}y\\
y = 3 \Rightarrow x = 2\\
CTHH:F{e_2}{O_3}
\end{array}\)
