Bạn tham khảo:
$1/$
$NaOH+HCl \to NaCl+H_2O$
$n_{NaOH}=1,25(mol)$
$n_{HCl}=1(mol)$
$HCl$ hết; $NaOH$ dư
$n_{NaOH}=n_{NaCl}=1(mol)$
$n_{NaOH}=(1,25-1).40=10(g)$
$n_{NaCl}=1.58,5=58,5(g)$
$2/$
$2H_2+O_2 \to 2H_2O$
$n_{H_2}=1,5(mol)$
$n_{O_2}=0,15625(mol)$
$O_2$ hết, $H_2$ dư
$n_{H_2O}=0,3125(mol)$
$m_{H_2O}=0,3125.18=5,625(g)$
$n_{H_2}=(1,5-0,3125).2=2,375(g)$
