Đáp án:
$⇒x=\dfrac{2}{11}$
Giải thích các bước giải:
$c) (\dfrac{1}{4}x-2)-\dfrac{3}{4}(4x-\dfrac{2}{3})=-3$
$⇒(\dfrac{1}{4}x-2)-3x-\dfrac{1}{2}=-3$
Cách làm:Phá ngoặc
$⇒\dfrac{1}{4}x-2-3x-\dfrac{1}{2}=-3$
Cách làm:Đưa về dấu cộng
$⇒\dfrac{1}{4}x+(-2)+(-3x)+\dfrac{-1}{2}=-3$
$⇒[\dfrac{1}{4}x+(-3x)]+(-2+\dfrac{-1}{2})=-3$
$⇒[x×(\dfrac{1}{4}+(-3)]+\dfrac{-5}{2}=-3$
$⇒x×\dfrac{-11}{4}=-3-\dfrac{-5}{2}$
$⇒x×\dfrac{-11}{4}=\dfrac{-1}{2}$
$⇒x=\dfrac{-1}{2}÷\dfrac{-11}{4}$
$⇒x=\dfrac{2}{11}$
