Đáp án:
$=\sqrt{2}$
Giải thích các bước giải:
$=(\sqrt[]{2-\sqrt{3}}-\sqrt{2+\sqrt{3}})/\sqrt{2}$
$=(\sqrt[]{4-2\sqrt{3}}-\sqrt{4+2\sqrt{3}})/\sqrt{2}$
$=(\sqrt[]{3-2\sqrt{3}+1}-\sqrt{3+2\sqrt{3}+1})/\sqrt{2}$
$=(\sqrt[]{(\sqrt{3}-1)^2}-\sqrt{(\sqrt{3}+1)^2})/\sqrt{2}$
$=(\sqrt{3}-1-\sqrt{3}-1)/\sqrt{2}$
$=\frac{-2}{\sqrt{2}}$
$=-\sqrt{2}$