Đáp án: $1)<$
$2)>$
$3)<$
Giải thích các bước giải:
1) Ta có:
`\frac{171717}{525252}=\frac{17.10101}{52.10101}=\frac{17}{52}`
`=\frac{17.55}{52.55}=\frac{935}{52.55}`
`\frac{232323}{555555}=\frac{23.10101}{55.10101}=\frac{23}{55}`
`=\frac{23.52}{52.55}=\frac{1196}{52.55}`
Do $935<1196$
`⇒\frac{935}{52.55}<\frac{1196}{52.55}`
`⇒\frac{171717}{525252}<\frac{232323}{555555}`
2) Ta có:
`\frac{21}{62}=\frac{21.79}{62.79}=\frac{1659}{62.79}`
`\frac{25}{79}=\frac{25.62}{62.79}=\frac{1550}{62.79}`
Do $1659>1550$
`⇒\frac{1659}{62.79}>\frac{1550}{62.79}`
`⇒\frac{21}{62}>\frac{25}{79}`
3) Ta có:
`\frac{-77}{99}=\frac{-7.11}{9.11}=\frac{-7}{9}`
`=\frac{-7.65}{9.65}=\frac{-455}{9.65}`
`\frac{-48}{65}=\frac{-48.9}{65.9}=\frac{-432}{65.9}`
Do $-455<-432$
`⇒\frac{-455}{9.65}<\frac{-432}{65.9}`
`⇒\frac{-77}{99}<\frac{-48}{65}`
