Đáp án+Giải thích các bước giải:
`|3/7x+1/2|=7/5`
`->` \(\left[ \begin{array}{l}\dfrac{3}{7}x+\dfrac{1}{2}=\dfrac{7}{5}\\\dfrac{3}{7}x+\dfrac{1}{2}=-\dfrac{7}{5}\end{array} \right.\) `->` \(\left[ \begin{array}{l}\dfrac{3}{7}x=\dfrac{9}{10}\\\dfrac{3}{7}x=-\dfrac{19}{10}\end{array} \right.\) `->` \(\left[ \begin{array}{l}x=\dfrac{21}{10}\\x=-\dfrac{133}{30}\end{array} \right.\)
Vậy `x\in{-133/30;21/10}`
