$v_o=14,4(km/h)=4(m/s)$
$v=0(m/s)$
$v^2-v_o^2=2as$
$\Rightarrow a=\dfrac{-8}{s}(m/s^2)$
PTCĐ: $s=4t-\dfrac{4t^2}{s}$
$t=10(s)\Rightarrow s_1=\dfrac{40s-400}{s}$
$t=20(s)\Rightarrow s_2=\dfrac{80s-1600}{s}$
Trong 10s kế tiếp, xe đi quãng đường $s_2-s_1(m)$
$\Rightarrow \dfrac{80s-1600-2(40s-400)}{s}=5$
$\Leftrightarrow -800=5s$
$\Rightarrow s=-160(m)$ (?)