Ta có: mC12H22O11 + mNaCl = 129,375 (g)
Gọi nC12H22O11=A , nNaCl=B
=>(12.12+1.22+16.11).A+(23+35,5).B =129,375
Hay 342.A+58,5.B=129,375
Ta lại có: 3.A=B
=>342.A+58,5.3.A=129,375
Hay 342.A+175,5.A=129,375
A.(342+175,5)=129,375
Hay A.517,5=129,375
A=129,375:517,5
A=0,25(mol)
Mà 3A=B
=>B=3.0,25=0,75(mol)
Vậy A=0,25 mol , B=0,75 mol