`a)(x^2-81)(x^2-36)=0`
`→` \(\left[ \begin{array}{l}x^2-81=0\\x^2-36=0\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x^2=81\\x^2=36\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=±9\\x=±6\end{array} \right.\)
Vậy `x∈{±9;±6}`
`b)15-(x+30)=16-(-x+5)-x`
`→15-x-30=16+x-5-x`
`→-x-x+x=16-5-15+30`
`→-x=26`
`→x=-26`
Vậy `x=-26`