Giải thích các bước giải:
\(\begin{array}{l}
\lim \dfrac{{ - {n^6} - 2{n^2} - \sqrt 3 n}}{{4{n^4} + 4{n^3} + 9{n^2}}}\\
= \lim \dfrac{{ - {n^5} - 2n - \sqrt 3 }}{{4{n^3} + 4{n^2} + 9n}}\\
= \lim \dfrac{{ - 1 - \dfrac{2}{{{n^4}}} - \dfrac{{\sqrt 3 }}{{{n^5}}}}}{{\dfrac{4}{{{n^2}}} + \dfrac{4}{{{n^3}}} + \dfrac{9}{{{n^4}}}}} = - \infty
\end{array}\)