Đáp án:
a. $\begin{array}{l}
I = 0,5\left( A \right)\\
{U_1} = 3\left( V \right)\\
{U_2} = 4,5\left( V \right)\\
{U_3} = 4\left( V \right)
\end{array}$
b.$\begin{array}{l}
{P_1} = 1,5\left( W \right)\\
{P_2} = 2,25\left( W \right)\\
{P_3} = 2\left( W \right)\\
P = 5,75\left( W \right)
\end{array}$
c.$3600\left( J \right)$
Giải thích các bước giải:
a.
$\begin{array}{l}
{R_1}nt{R_2}nt{R_3}\\
{R_{td}} = {R_1} + {R_2} + {R_3} = 23\\
I = \frac{E}{{{R_{td}} + r}} = \frac{{12}}{{23 + 1}} = 0,5\left( A \right)\\
{U_1} = I.{R_1} = 0,5.6 = 3\left( V \right)\\
{U_2} = I.{R_2} = 0,5.9 = 4,5\left( V \right)\\
{U_3} = I.{R_3} = 0,5.8 = 4\left( V \right)
\end{array}$
b
$\begin{array}{l}
{P_1} = {I^2}.{R_1} = 1,5\left( W \right)\\
{P_2} = {I^2}.{R_2} = 2,25\left( W \right)\\
{P_3} = {I^2}.{R_3} = 2\left( W \right)\\
P = {P_1} + {P_2} + {P_3} = 5,75\left( W \right)
\end{array}$
c
$A = E.I.t = 12.0,5.10.60 = 3600\left( J \right)$