Nguyên hàm $I=\int{{\frac{x}{{3x+\sqrt{{9{{x}^{2}}-1}}}}dx}}$ bằng?
A. $I=\frac{1}{9}{{\left( {9{{x}^{2}}-1} \right)}^{{\frac{3}{2}}}}+{{x}^{3}}+C.$
B. $I=\frac{1}{{27}}{{\left( {9{{x}^{2}}-1} \right)}^{{\frac{3}{2}}}}+{{x}^{3}}+C.$
C. $I=\frac{1}{9}{{\left( {9{{x}^{2}}-1} \right)}^{{\frac{3}{2}}}}-{{x}^{3}}+C.$
D. $I=\frac{1}{{27}}{{\left( {9{{x}^{2}}-1} \right)}^{{\frac{3}{2}}}}-{{x}^{3}}+C.$
A. $I=\frac{1}{9}{{\left( {9{{x}^{2}}-1} \right)}^{{\frac{3}{2}}}}+{{x}^{3}}+C.$
B. $I=\frac{1}{{27}}{{\left( {9{{x}^{2}}-1} \right)}^{{\frac{3}{2}}}}+{{x}^{3}}+C.$
C. $I=\frac{1}{9}{{\left( {9{{x}^{2}}-1} \right)}^{{\frac{3}{2}}}}-{{x}^{3}}+C.$
D. $I=\frac{1}{{27}}{{\left( {9{{x}^{2}}-1} \right)}^{{\frac{3}{2}}}}-{{x}^{3}}+C.$
Loga
Hóa Học lớp 12
