Bạn tham khảo:
$a/$
$Fe+2HCl \to FeCl_2+H_2$
$n_{Fe}=\frac{5,6}{56}=0,1(mol)$
$n_{H_2}=n_{Fe}=0,1(mol)$
$V_{H_2}=0,1.22,4=2,24(l)$
$b/$
$Zn+2HCl \to ZnCl_2+H_2$
$n_{HCl}=0,1.0,1=0,01(mol)$
$n_{Zn}=\frac{0,01}{2}=0,005(mol)$
$m_{Zn}=0,005.65=0,325(g)$
$c/$
$Mg+2HCl \to MgCl_2+H_2$
$Fe+2HCl \to FeCl_2+H_2$
$n_{Mg}=a(mol)$
$n_{Fe}=b(mol)$
$m_{hh}=24a+56b=10,4(1)$
$n_{H_2}=a+b=\frac{6,72}{22,4}=0,3(2)$
$(1)(2)$
$a=0,2$
$b=0,1$
$m_{Mg}=0,2.24=4,8(g)$
$m_{Fe}=0,1.56=5,6(g)$
$m_{muoi}=0,2.95+0,1.127=31,7(g)$
