Em tham khảo nha :
\(\begin{array}{l}
a)\\
{m_{Fe}} = \dfrac{{242 \times 46,289}}{{100}} = 112g\\
{m_{Zn}} = 242 - 112 = 130g\\
b)\\
Fe + {H_2}S{O_4} \to FeS{O_4} + {H_2}\\
Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2}\\
{n_{Fe}} = \dfrac{{112}}{{56}} = 2mol\\
{n_{Zn}} = \dfrac{{130}}{{65}} = 2mol\\
{n_{{H_2}}} = {n_{Fe}} + {n_{Zn}} = 4mol\\
{V_{{H_2}}} = 4 \times 22,4 = 89,6l\\
c)\\
{n_{FeS{O_4}}} = {n_{Fe}} = 2mol\\
{m_{FeS{O_4}}} = 2 \times 152 = 304g\\
{n_{ZnS{O_4}}} = {n_{Zn}} = 2mol\\
{m_{ZnS{O_4}}} = 2 \times 161 = 322g
\end{array}\)
