Program btmang;
Uses crt;
Var
max,min,i,j,s,k,bi: Longint;
a : Array [1..10,1..10] Of Integer;
b: Array [1..50] Of Integer;
Begin
Clrscr;
For i:= 1 To 5 Do
For j:= 1 To 3 Do
Begin
Write('Nhap a[',i,',',j,']');
read(a[i,j]);
Clrscr;
End;
Write('Nhap k : ');
read(k);
Clrscr;
Writeln('Mang 3x5 : ');
For i:= 1 To 5 Do
Begin
For j:= 1 To 2 Do
Write(a[i,j],' ');
Writeln(a[i,3]);
End;
s := 0;
For i:= 1 To 5 Do
For j:= 1 To 3 Do
s := s+a[i,j];
Writeln('Tong cac phan tu trong mang la : ',s);
bi := 0;
For i:= 1 To 5 Do
For j:=1 To 3 Do
If a[i,j] < k Then
Begin
Inc(bi);
b[bi] := a[i,j];
End;
If bi = 0 Then Writeln('Khong co phan tu nao cua mang nho hon ',k,'.')
Else
Begin
Writeln('Cac phan tu nho hon ',k,' la : ');
For i:= 1 To bi-1 Do
Write(b[i],' ');
writeln(b[bi]);
End;
min := a[1,1];
max := a[1,1];
For i:= 1 To 5 Do
For j:= 1 To 3 Do
Begin
If a[i,j] > max Then max := a[i,j];
If a[i,j] < min Then min := a[i,j];
End;
Writeln('Phan tu nho nhat la :',min,', phan tu lon nhat la : ',max);
Readln;
End.