Em tham khảo nha :
\(\begin{array}{l}
{n_{C{O_2}}} = \dfrac{{4,48}}{{22,4}} = 0,2mol\\
{n_{KOH}} = 0,12 \times 2 = 0,24mol\\
T = \dfrac{{{n_{KOH}}}}{{{n_{C{O_2}}}}} = \dfrac{{0,24}}{{0,2}} = 1,2\\
\Rightarrow {K_2}C{O_3},KHC{O_3}\\
KOH + C{O_2} \to KHC{O_3}\\
2KOH + C{O_2} \to {K_2}C{O_3} + {H_2}O\\
hh:{K_2}C{O_{.3}}(a\,mol),KHC{O_3}(b\,mol)\\
\left\{ \begin{array}{l}
a + b = 0,2\\
2a + b = 0,24
\end{array} \right.\\
\Rightarrow a = 0,04;b = 0,14\\
{C_{{M_{{K_2}C{O_3}}}}} = \dfrac{{0,04}}{{0,12}} = \dfrac{1}{3}M\\
{C_{{M_{KHC{O_3}}}}} = \dfrac{{0,14}}{{0,12}} = 1,167M
\end{array}\)
