Câu 1: a.m>n
`m= 1 +2+ 2^2 +....+ 2^2008`
`2m =2+ 2^2 + 2^3 +....+ 2^2009`
`2m-m= (2+ 2^2 + 2^3 +....+ 2^2009) - (1 +2+ 2^2 +....+ 2^2008)`
`m= 2^2009 -1`
Vì `m= 2^2009 -1 > n=2^(2009 -1)`
Câu 2: b.986
`(2x +2^5 ).2004^5 =2004^6`
`2x + 2^5 = 2004`
`2x +32=2004`
`2x=1972`
`x=986`