Giải thích các bước giải:
Phản ứng xảy ra:
\(F{\text{e}} + S\xrightarrow{{{t^o}}}F{\text{e}}S\)
\(F{\text{e}}S + 2HCl\xrightarrow{{}}F{\text{e}}C{l_2} + {H_2}S\)
\(F{\text{e}} + 2HCl\xrightarrow{{}}F{\text{e}}C{l_2} + {H_2}\)
Ta có:
\({n_{{H_2}}} + {n_{{H_2}S}} = \dfrac{{4,48}}{{22,4}} = 0,2{\text{ mol = }}{{\text{n}}_{F{\text{e}}}} + {n_{F{\text{e}}S}} = {n_{F{\text{e ban đầu}}}}\)
\( \to {m_{F{\text{e}}}} = 0,2.56 = 11,2{\text{ gam}}\)
\( \to \% {m_{F{\text{e}}}} = \dfrac{{11,2}}{{14,4}}.100\% = 77,78\% \to \% {m_S} = 22,22\% \)